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2 years ago

Which of the following is equivalent to 5√12 - 2√27?

Mathematics

2 answers:

Marizza181 [45]2 years ago

8 0

4 square root 3 just trust

DerKrebs [107]2 years ago

5 0

Answer:

A. 4 root 3

Step-by-step explanation:

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Ned is riding his bike from his house to the park, both of which are on the same straight road. On his way, he stops at a store,

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Answer:

Step-by-step explanationcl:

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4 years ago

When is my dad coming back from the store with milk?

joja [24]

Answer:

Don't know, it's one of the worlds greatest mysteries.

I know that much cause I waiting for mine to come back too!

Step-by-step explanation:

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3 years ago

The difference of a number c and 17 is more than 33.

tester [92]

Answer:

c-17=x>33

c=51

Step-by-step explanation:

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3 years ago

URGENT: Click on the graph to choose the correct answer to the equation.<br><br>x > 2

balandron [24]

Answer:

The 4th graph.

Step-by-step explanation:

Its a horizontal line which indicates that x is known and the line begins over 2.

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3 years ago

The secretary in Exercises 2.121 and 3.16 was given n computer passwords and tries the passwords at random. Exactly one of the p

Vlada [557]

Answer:

There is a $\frac{(n-1)^{5}}{n^{6}}$ probability that the correct password is found on the sixth try.

Step-by-step explanation:

We have n passwords, only 1 is correct.

So,

Since a password is put back with other, at each try, we have that:

The probability that a password is correct is $\frac{1}{n}$

The probability that a password is incorrect is $\frac{n-1}{n}$ .

There are 6 tries.

We want the first five to be wrong. So each one of the first five tries has a probability of $\frac{n-1}{n}$ . So, for the first five tries, the probability of getting the desired outcome is $\frac{(n-1)^{5}}{n^{5}}$ .

We want to get it right at the sixth try. The probability of sixth try being correct is $\frac{1}{n}$ .

So, the probability that the first five tries are wrong AND the sixth is correct is:

$P = \frac{(n-1)^{5}}{n^{5}}\frac{1}{n} = \frac{(n-1)^{5}}{n^{6}}$

There is a $\frac{(n-1)^{5}}{n^{6}}$ probability that the correct password is found on the sixth try.

5 0

3 years ago