Y+4−1=18 i need help plz
2 answers:
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See the attached figure to better understand the problem
we know that
in the triangle ABC
tan 15=AC/BC--------> AC=BC*tan 15
BC=51 m
AC=51*tan 15------> AC=13.67 m
t<span>he height of the shorter building=207-AC----> 207-13.67----> 193.33 m
</span>the height of the shorter building=193 m
<span>
the answer Part a) is
</span>the height of the shorter building is 193 m
<span>
Part b) </span><span>how does the angle of depression from the top of the taller building relate to the angle of elevation from the top of the shorter building
</span>
we know that
the angle of depression is equals to the angle of elevation
so
the answers are
<span>A:They are congruent
</span><span>D:They are alternate interior angles</span>
we know that
in the triangle ABC
tan 15=AC/BC--------> AC=BC*tan 15
BC=51 m
AC=51*tan 15------> AC=13.67 m
t<span>he height of the shorter building=207-AC----> 207-13.67----> 193.33 m
</span>the height of the shorter building=193 m
<span>
the answer Part a) is
</span>the height of the shorter building is 193 m
<span>
Part b) </span><span>how does the angle of depression from the top of the taller building relate to the angle of elevation from the top of the shorter building
</span>
we know that
the angle of depression is equals to the angle of elevation
so
the answers are
<span>A:They are congruent
</span><span>D:They are alternate interior angles</span>
Check the picture.
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"