First translate into an equation. Then solve
N=non-negative integers.
2(n^2) = 4n. Divide both sides of = by 2
n^2 = 2n subtract 2n from both sides
n^2 - 2n = 0. Factor
n(n - 2) =0. Solve factor = 0.
N = 0. N-2= 0
+2. +2
N= 2
So 0 & 2 are both answers
Answer:
C
Step-by-step explanation:
Rectangle: 8*5=40
Triangle 1: (3*5)/2=7.5
Triangle 2: (3*5)/2=7.5
Trapezoid : 40+7.5+7.5=55
Answer:
2nd and 3rd choices
Step-by-step explanation:
use h(t) = h(0) + v(0)t + at^2/2
Now h(0) = 18, v(0) = 0, a = -9.8
so h(t) = 18 - 4.9 t^2
Solve h(t) = 18 - 4.9 t^2 = 0
Get t = 1.92 sec
We are required to find the total milligrams if medicine the hospital can get from the three companies.
The total quantity of medicine the hospital can get from the three companies is 2.75 milligrams
There are there companies:
Company A
Company B
Company C
Company A = 1.3 milligrams
Company A is 0.9 milligrams more than Company C's
A = 0.9 + C
1.3 = 0.9 + C
1.3 - 0.9 = C
0.4 = C
C = 0.4 milligrams
Company A is also twice the difference between the weight of
Company B's supply and Company C's
A = 2(B - C)
1.3 = 2(B - 0.4)
1.3 = 2B - 0.8
1.3 + 0.8 = 2B
2.1 = 2B
Divide both sides by 2
B = 2.1/2
B = 1.05 milligrams
Therefore,
A + B + C
= 1.3 + 1.05 + 0.4
= 2.75 milligrams
Read more:
brainly.com/question/24562139
Step-by-step explanation:
for part a
initial means starting point and starting point is always 0
so the question means number of thousands of bacteria in 0 hours, your n being the number of hours. so in part a u will simply just put 0 as n in equation
2^(0+3)
2³=8 thousands of bacteria
in part b
2^(n+3) means total number of bacteria
2^(n-1) is number of groups
its asking for number of bacteria in each group
so u will simply divide number of bacteria by groups
its like u have 30 candies and there are 5 groups and they ask u to find number of candies in each group so u simply divide 30 by 5
so 2^(n+3)/2^(n-1)
base is same so powers will subtract since there is division sign
2^(n+3-(n-1))
2^(n+3-n+1)
2^(3+1)
2^4= 16 thousands of bacteria in each group
