In probability, problems involving arrangements are called combinations or permutations. The difference between both is the order or repetition. If you want to arrange the letters regardless of the order and that there must be no repetition, that is combination. Otherwise, it is permutation. Therefore, the problem of arrange A, B, C, D, and E is a combination problem.
In combination, the number of ways of arranging 'r' items out of 'n' items is determined using n!/r!(n-r)!. In this case, you want to arrange all 5 letters. So, r=n=5. Therefore, 5!/5!(505)! = 5!/0!=5!/1. It is simply equal to 5! or 120 ways.
That decimal is equivalent to
45,833,333,333 / 100,000,000,000 .
If the numerator and denominator have any common factor,
then the fraction can be simplified. But I doubt it.
Mark would have ran 6 miles if he ran 9.654 kilometers
Answer:
B
Step-by-step explanation:
The volume (V) is calculated as
V = area of triangular face × depth
Area of triangle = 
bh ( b is the base and h the height )
Here b = 3 and h = 4 , then
A = × 3 × 4 = 6 Km²
Now depth = 2, thus
V = 6 × 2 = 12 Km³ → B
Step-by-step explanation:
let the University of Miami enrolment be x
so the University of Texas at Austin has three times = 3x
The University of California, Berkley has 3,000 more than twice the number of students at the University of Miami.
this can be translated as = 3000+2x
in total, the enrolment is 96,000
therefore
x+3x+3000+2x=96000
we can now solve for x
6x=96000-3000
6x=93000
divide both sides by 6 we have
x=15500
1. The University of Miami enrolment is 15500 students
2. The University of Texas at Austin has three times = 3x
=3*15500
= 46500 students
3. The University of California, Berkley has
= 3000+2x
= 3000+2(15500)
=3000+46500
=49500 students
