6x3=18
The room is 18ft long
100/2=50
The park is 50mm long
Answer:
a) 0.32
b) 0.68
c) office or den
Step-by-step explanation:
Locations Probabilities
Adult bedroom 0.03
Child bedroom 0.15
Other bedroom 0.14
Office or den 0.40
Other rooms 0.28
a)
P(PC in bedroom)= P(PC in adult bedroom)+ P(PC in child bedroom)+ P(PC in other bedroom)
P(PC in bedroom)= 0.03+0.15+ 0.14
P(PC in bedroom)= 0.32.
Thus, the probability that a PC is in a bedroom is 0.32.
b)
P(PC is not in bedroom)= P(PC in Office or den)+ P(PC in Other rooms)
P(PC is not in bedroom)= 0.40+0.28
P(PC is not in bedroom)= 0.68.
Thus, the probability that a PC is not in a bedroom is 0.68.
c)
When a household is selected at random from households with a PC we would expect to find a PC in a room which has a greater probability of having PC.
The greater probability of room having a PC is of Office or den room with probability 0.40. So, when a household is selected at random from households with a PC we would expect to find a PC in a Office or den room.
Vertical angles are always equal.
x = 130
That's your answer.
Have an awesome day! :)
Answer:
divide
Step-by-step explanation:
divide 26.216 and 128 to get ur anser
