Ask question

Ask question

All categories

3 years ago

9

Someone help pls :CCCCC its math

2 answers:

Nutka1998 [239]3 years ago

3 0

6x3=18

The room is 18ft long

100/2=50

The park is 50mm long

emmasim [6.3K]3 years ago

3 0

Answer:

The room is 18ft long

the park is 50mm long hope it helped

Step-by-step explanation:

You might be interested in

Yesterdays low temperature was -2.5°C today low temperature is five times as lone as yesterday’s low temperature

zimovet [89]

Answer:

-12.5°C

Step-by-step explanation:

To solve this problem you would multiply -2.5 by 5.

-2.5 * 5 = -12.5

Today's low temperature is -12.5°C.

6 0

2 years ago

What major key has the same number of sharps and flats as the key of a minor. A. A major B. F major C. C major D. G major This i

FrozenT [24]

Answer:

C major

Step-by-step explanation:

major key has the same number of sharps and flats as the key of minor.

7 0

2 years ago

Factor the GCF: 12a3b + 8a2b2 − 20ab3

Harrizon [31]

<span>12a^3b + 8a^2b^2 − 20ab^3

</span>12a^3b = 4ab(3a^2)
8a^2b^2 = 4ab(2ab)
20ab^3 = 4ab(5b^2)

GCF = 4ab

12a3b + 8a2b2 − 20ab3 = 4ab(3a^2 + 2ab - 5b^2)

6 0

3 years ago

Read 2 more answers

What is the value of a in simplest form?

devlian [24]

Answer:

$x^4$

Step-by-step explanation:

$\frac{x^{3} }{\sqrt[6]{x}}$

$((\sqrt{x})^{2})(x^{3} )$

$(x)(x^3)\\x^4$

6 0

3 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

as

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago