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Reil [10]
1 year ago
12

A portion of the Quadratic Formula proof is shown. Fill in the missing reason.

Mathematics
1 answer:
katrin [286]1 year ago
6 0

The quadratic equation ax²+bx+c = 0 is given and this is illustrated below.

<h3>How to illustrate the equation?</h3>

ax²+bx+c = 0

Step 1: Subtract c from both sides

ax²+bx+c-c = 0-c

ax²+bx = -c

Step 2: Divide both sides of the equation by a

ax²/a + bx/a = -c/a

x² + bx/a = -c/a

Step 3: Complete the square and add the quantity (b/2a)² times a squared to both sides

x² + bx/a +  (b/2a)² = -c/a +  (b/2a)²

Step 4: Square the quantity b/2a on the right side of the equation

x² + bx/a +  (b/2a)² =  -c/a +  b²/4a²

Step 5: Find a common denominator on the right side of the equation which is 4a²

x² + bx/a +  (b/2a)² =  -4ac/4a² +  b²/4a²

Step 6: Add the fractions together on the right side of the equation

x² + bx/a +  (b/2a)² =  (-4ac+  b²)/4a²

Step 7: The equation on the left is to be written as a perfect square as shown

(x+b/2a)² =  (-4ac+  b²)/4a²

Step 8: Take the square root of both sides

√(x+b/2a)² = √ (-4ac+  b²)/4a²

(x+b/2a) =  √(-4ac+  b²)/2a

Step 9: subtract b/2a from both sides

x+b/2a - b/2a =  -b/2a + √(-4ac+  b²)/2a

x =  -b/2a + √(-4ac+  b²)/2a

Step 10: Add the fractions together on the right-hand side

x =  -b±√(-4ac+  b²)/2a

This will then gives the required equation.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

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Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
3 years ago
7n + 5n2 + 10 – 7n<br><br> Simplify the expression
Travka [436]

Answer:

10n+10

Step-by-step explanation:

7n-7n+5n2+10

5n2+10

5n*2+10

10n+10

Hope this helps :D

#Team Rainbows

7 0
3 years ago
Solve x - 20 &gt; -15, and then graph the solutions. Use pencil and paper. Explain how
Artyom0805 [142]

Answer: x ≥ 6

Step-by-step explanation:

So 6 - 20 would equal -14 which is greater than -15 making it our inequality equal to or greater then 6

8 0
3 years ago
How do I do this table !!!
erma4kov [3.2K]

Answer:

Step-by-step explanation:

just mutiply  120 by 1,2,3,4,5,6,7,8

7 0
3 years ago
nA car dealer who sells only late-model luxury cars recently hired a new salesperson and believes that this salesperson is selli
7nadin3 [17]

Answer:

The value of an appropriate test statistic for the car dealer to use is -4.

Step-by-step explanation:

The null hypothesis is:

H_{0} = 4600

The alternate hypotesis is:

H_{1} < 4600

The test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

In this problem:

X = 4100, \mu = 4600, \sigma = 500, n = 16

Then

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{4100 - 4600}{\frac{500}{\sqrt{16}}}

t = -4

The value of an appropriate test statistic for the car dealer to use is -4.

8 0
3 years ago
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