Each side of a rhombus is 20 cm long and one of its diagonals is 24 cm in length, find the area of this rhombus?
2 answers:
<h3>Given :</h3>
- Diagonal_1 of rhombus = 24 cm

<h3>To find :</h3>

<h3>Note :</h3>
Kindly keep in touch with picture

<h3>Solution:</h3>
We know:

As we can clearly see we need both diagonals, but in question only one diagonal is given.

So first let's find other diagonal.



In △ AOB :
AB - Hypotenuse
AO = Perpendicular
BO = Base

Base² = Hypotenuse ² - Perpendicular²
∴ BO² = AB² - AO²
- BO² = 20² - 12²
- BO² = 400 - 12²
- BO² = 400 - 144
- BO² = 256
- BO = √(256)
- BO = √(16 × 16)
- BO = 16 cm²

- Diagonal_2 = 2BO
- Diagonal_2 = 2 × 16
- Diagonal_2 = 32 cm



As we already know Area of rhombus so :







Answer:
AB = 20 CM
OA = 1
__ × 24 cm
2
= 12 cm
AOB = 90 °
OB² == AB² - OA ²


AREA OF ABCD IS


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