Each side of a rhombus is 20 cm long and one of its diagonals is 24 cm in length, find the area of this rhombus?
2 answers:
<h3>Given :</h3>
Diagonal_1 of rhombus = 24 cm
<h3>To find :</h3>
<h3>Note :</h3>
Kindly keep in touch with picture
<h3>Solution:</h3>
We know:
As we can clearly see we need both diagonals, but in question only one diagonal is given.
So first let's find other diagonal.
In △ AOB :
AB - Hypotenuse
AO = Perpendicular
BO = Base
Base² = Hypotenuse ² - Perpendicular²
∴ BO² = AB² - AO²
BO² = 20² - 12² BO² = 400 - 12² BO² = 400 - 144 BO² = 256 BO = √(256) BO = √(16 × 16) BO = 16 cm²
Diagonal_2 = 2BO Diagonal_2 = 2 × 16 Diagonal_2 = 32 cm
As we already know Area of rhombus so :
Answer:
AB = 20 CM
OA = 1
__ × 24 cm
2
= 12 cm
AOB = 90 °
OB² == AB² - OA ²
AREA OF ABCD IS
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