A (-2,1) -> A'(1,-2)
B (-3,4)-> B'(4,-3)
C (-4,1) -> C'(1,-4)
(X,Y) -> (Y,X)
I believe the answer is <span>$30 a week</span>
<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
Answer:
2 * 2 * 5 * 5, or 2^2 * 5^2, or 5^2 * 2^2
Step-by-step explanation:
You can use a factoring tree to find the prime factorization of 100.
+------ 100----------------+
| |
2 +---50---------+
| |
2 +----25----+
| |
5 5
The prime factorization of 100 is 2 * 2 * 5 * 5, or 2^2 * 5^2, or 5^2 * 2^2