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Nezavi [6.7K]
3 years ago
10

Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d

. -18, -81, -144
Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0
<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144

Solution:

Since  it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.

for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!

for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d

they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
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Answer:

21\frac{3}{4}

Step-by-step explanation:

Step 1: Add the numbers.

20.25 can also be expressed as 20\frac{1}{4}, because \frac{2025}{100} = \frac{81}{4} = 20\frac{1}{4}. So if we add 20\frac{1}{4} and 11, we would get 31\frac{1}{4}

Step 2: Solve

31\frac{1}{4} -9\frac{1}{2}

  • Subtract the whole numbers

31-9=21

  • Combine the fractions

This means addition. Also, since our denominators are not the same value, we have to find the LCM (Least Common Denominator): What do 2 and 4 have in common that they can divide themselves by? 4. We know this because 2 divided by 4 is 2, and 4 divided by 4 is 1, so they can both divide themselves by 4.

\frac{5}{4}-\frac{1}{2}

LCM

\frac{5}{4}-\frac{2}{4} =\frac{3}{4}

Therefore, the simplified expression to this is 21\frac{3}{4}.

Learn more: brainly.com/question/403991

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To the nearest​ millimeter, a cell phone is 114 mm long and 69 mm wide. What is the ratio of the width to the​ length
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The diameter of a coin is 26mm. Mathew lined up 56 coins from the left end of his desk to the right end of his desk. What is the
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Answer:

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Step-by-step explanation:

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Hope I helped!

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Pls Help Psl help brainliest
kumpel [21]
X=31, the other post justifies, I just wanted to make it more accessible for if someone just needs the answer :)
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