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saveliy_v [14]
2 years ago
8

There are two conditions under which we can assume that the sample means follow a normal distribution. What are they

Mathematics
1 answer:
Naddik [55]2 years ago
5 0

Two conditions under which we can assume that the sample means follow a normal distribution are as follows:

1). If the sample size is large​ enough, n greater than or equals 30, the sampling distribution is approximately normal regardless of the shape of the population.

2). In order to be considered a normal distribution, a data set (when graphed) must follow a bell-shaped symmetrical curve centered around the mean.

To learn more about Normal Distributions visit:

brainly.com/question/4079902

#SPJ4

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What is the midpoint of (-2,-2) and (2,6)
marin [14]

Answer:

(0,2)

Step-by-step explanation:

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3 years ago
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(X^2+x-6)(2x^2+4x) factor completely
MissTica

Answer:

2x\left(x-2\right)\left(x+3\right)\left(x+2\right)

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring x^2+x-6.

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For ax^2+bx+c we need to find u, v > u\cdot \:v=a\cdot \:c and u+v=b which we will group into \left(ax^2+ux\right)+\left(vx+c\right).

The values we have are...a=1,\:b=1,\:c=-6 and u\cdot v=-6,\:u+v=1.

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow  \mathrm{True}

\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow  \mathrm{False}

Therefore u=3,\:v=-2.

Now we want to \mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right). Which is \left(x^2-2x\right)+\left(3x-6\right).

Now we must factor x from x^2-2x.

Lets apply the exponent rule of a^{b+c}=a^ba^c which means x^2=xx.

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of 3x-6.

Rewrite 6 as 3 * 2. 3x-3\cdot \:2.

Now factor out the common term of 3 > 3\left(x-2\right).

x\left(x-2\right)+3\left(x-2\right) > Factor out the common term of x - 2 > \left(x-2\right)\left(x+3\right).

Now lets factor 2x^2+4x.

Apply the previous exponent rule of a^{b+c}=a^ba^c > x^2=xx > 2xx+4x.

Now rewrite 4 as 2 * 2 > 2xx+2\cdot \:2x.

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get 2x\left(x-2\right)\left(x+3\right)\left(x+2\right).

Hope this helps!

7 0
3 years ago
Using an old post still need help
finlep [7]

Answer:

12x+20

Step-by-step explanation:

2(5x+2)+2(x+8)

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10x+4+2x+16=12x+20

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Juan lives 100 m away from billy. what is juans average speed if he reaches billys home in 50 seconds
alexandr1967 [171]

Answer:

3 meters per second

Step-by-step explanation:

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3 years ago
What is the volume of the plastic rocket???
Marina86 [1]

Answer:

151 in^3

Step-by-step explanation:

The rocket consists of two shapes - a cone and a cylinder

the volume of the plastic = volume of cone + volume of cylinder

volume of a cylinder = nr^2h

Volume of a cone 1/3(nr^2h)

n = 22/7  

r = radius

the diameter is the straight line that passes through the center of a circle and touches the two edges of the circle.

A radius is half of the diameter

Radius = 5/2 = 2.5

Height of cone = 11 - 6 = 5

Volume of plastic = (22/7) x (2/5^2) x 6  + (1/3) x (22/7) x (2/5^2) x 5 = 117.9 + 32.7 = 150.6 in^3 = 151

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3 years ago
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