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saveliy_v [14]
2 years ago
8

There are two conditions under which we can assume that the sample means follow a normal distribution. What are they

Mathematics
1 answer:
Naddik [55]2 years ago
5 0

Two conditions under which we can assume that the sample means follow a normal distribution are as follows:

1). If the sample size is large​ enough, n greater than or equals 30, the sampling distribution is approximately normal regardless of the shape of the population.

2). In order to be considered a normal distribution, a data set (when graphed) must follow a bell-shaped symmetrical curve centered around the mean.

To learn more about Normal Distributions visit:

brainly.com/question/4079902

#SPJ4

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What is the standard form of the linear function that passes
babunello [35]

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{4}}}\implies \cfrac{-3}{-2}\implies \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{4})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2(y-1)=2\left( \cfrac{3}{2}(x-4) \right)}\implies 2y-2 = 3(x-4)\implies 2y-2=3x-12 \\\\\\ -3x+2y-2=-12\implies -3x+2y=-10\implies \stackrel{\times -1\textit{ to both sides}}{3x-2y=10}

7 0
2 years ago
Sum of 5 times of x and thrice of y is 106​
Lostsunrise [7]

Answer:

<h3>sum of 5 times of x and thrice of y is 106</h3>

\huge \boxed{5x + 3y = 106}

8 0
3 years ago
Read 2 more answers
In an 18-meter race between a tortoise and a hare, the tortoise leaves 23 minutes before the hare. The hare, by running at an av
seropon [69]
We know that:
time=distance/speed
if the tortoise speed is x m/min, then since 0.5 m/hr=1/120 m/min
18/x=23+18/(x+1/120)
solving for x we get:
x=0.08 m/min
speed of hare is:
(0.08+1/120)=0.088 m/min

6 0
3 years ago
Evaluate cos 25o to four decimal places.
Firdavs [7]

\tt \cos(25)  = 0.991203 \: or \: 0.99

8 0
2 years ago
Paralell to y=4x-6 through (12,10)
stiks02 [169]

<u>ANSWER</u>

The line that is parallel to y=4x-6 through (12,10) is  y=2x-14.



<u>EXPLANATION</u>


The equation that is parallel to the line y=4x-6 has a slope that is equal to the slope of this line.

By comparing this equation to the general slope intercept form,

y=mx+c,this line has slope m=2.


Hence the line parallel to this line also has slope m=2.

Let y=mx+b be the equation of the line parallel to the line

y=4x-6

We can substitute m=2 to obtain;

y=2x+b


If the line passes through the point (12,10),then this point must satisfy its equation.


We substitute x=12 and y=10 to obtain;


10=2(12)+b


We this equation for b.


\Rightarrow 10=24+b


\Rightarrow 10-24=b


\Rightarrow -14=b


We substitute this value of  b=-14 in to y=2x+b to get;


y=2x+-14.


Hence the equation of the line that is parallel to y=4x-6 through (12,10) is  y=2x-14.




3 0
3 years ago
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