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Alborosie
3 years ago
7

What is the point-slope form of a line with slope 3 that contains the point

Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0

Answer:

y-1 = 3(x-2)

Step-by-step explanation:

Point slope form is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

y-1 = 3(x-2)

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Which line shows the graph of y = 4x - 5 reflected over the y-axis?
elena-14-01-66 [18.8K]

Answer:

The line y = -4x - 5 shows the reflection over the y-axis.

From the attached graph, the blue line i.e. y = -4x-5 represents the reflection over the y-axis.

Step-by-step explanation:

When we reflect a line function over the y-axis, all we need is to negate the x-coordinate or value of 'x', while y-coordinate or y-value remains the same.

Given the function

y = 4x-5

replace x with -x

y = 4(-x) - 5

y = -4x - 5

Thus, the line y = -4x - 5 shows the reflection over the y-axis.

From the attached graph, the blue line i.e. y = -4x-5 represents the reflection over the y-axis.

From the graph, it is clear that that that x-coordinate of y = 4x-5 is negated.

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3 years ago
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Artemon [7]

Answer:

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Step-by-step explanation:


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4 years ago
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Answer:

Heres how you do it

Step-by-step explanation:

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1. Write an equation in point-slope form of the line that that passes through the point (4,-5) and has a
Aleks04 [339]

Answer:

y + 5 = (3/2)(x - 4)

Step-by-step explanation:

The point-slope formula is y - k = m(x - h).  We get h and k from the given point:  h = 4 and k = -5, and m from the given slope:  3/2.  Then we have:

y + 5 = (3/2)(x - 4)

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3 years ago
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