1295x32= 41440
1362x40=54480
1.181x23=27163
Hope this helped
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Please post the question ..i'll solve for x
She would have $904. 275 + 812= 1087. 75 + 60 + 48= 183. 1087 - 183 = 904. Check the math to make sure, I did it in my head.
Your answer: 2/3/2/9 = 0.037037037037037
