Answer:
a) λ = 435 nm
, c) c) λ = 4052 nm, d) λ= 95 nm
Explanation:
A) To carry out this excitation, the energy of the laser must be greater than or equal to the energy of the transition of the hydrogen atom, whose states of energy are described by the Bohr model.
En = -13,606 / n² [eV]
therefore the energy of the transition is
ΔE = E₅ -E₂
ΔE = 13.606 (1 / n₂² - 1 / n₅²)
ΔE = 13.606 (1/2² - 1/5²)
ΔE = 2,85726 eV
now let's use Planck's equation
E = h f
the speed of light is related to wavelength and frequencies
c = λ f
f = c /λ
E = h c /λ
λ = h c / E
let's reduce the energy to the SI system
E = 2,85726 eV (1.6 10⁻¹⁹ J / 1 eV) = 4.5716 10⁻¹⁹ J
let's calculate
λ = 6,626 10⁻³⁴ 3 10⁸ / 4,5716 10⁻¹⁹
λ = 4.348 10⁺⁷ m (10⁹ nm / 1 m)
λ = 435 nm
B) photon emission processes from this state with n = 5 to the base state n = 1, can give transition
initial state n = 5
final state n = 4
ΔE = 13.606 (1/4² - 1/5²)
ΔE = 0.306 eV
λ = h c / E
λ = 4052 nm
n = 5
final ΔE (eV) λ (nm)
level
4 0.306 4052
3 0.9675 1281
2 2,857 435
1 13.06 95
n = 4
3 0.661 1876
2 2,551 486
1 11,905 104
n = 3
2 1.89 656
1 12.09 102.5
n = 2
1 10.20 121.6
c) λ = 4052 nm
d) λ= 95 nm
Answer:
see below
Explanation:
to find distance multiply speed by time
to compute speed the formula is distance divided by time
here is to learn the triangle
Search up distance, speed and time triangle
it is much easier to remember
hope this helps
please mark it brainliest
Answer:
basic quantity. s.I unit. equipment
length M or Cm . metre rule
mass. Kg or G. spring/weight balance
time. Seconds. clock/stopwatch
Temperature. kelvin/celcius thermometer
volume. L/Ml/Cl. measuring cylinder
Answer:
7.15/2 = 3.575m
1.78cos(45.4) = 1.25m
radius = 3.575 + 1.25 = 4.825 m
mg of seat = 10 x 9.8 = 98 N
98/sin(45.4) = 137.64 N
Horizontal force = 137.64cos(45.4) = 96.64 N
Centripetal force = 96.64 N
96.64/10 = 9.6644 = ca
9.6644 x 4.825 = v^2 = 46.63, sq-root = v = 6.83 m/s
(10 + 28.3) x 9.8 = mg = 375.34 N
375.34/sin(45.4) = 527.14 N
Explanation:
Answer:
0.95 m/s
Explanation:
Find the vertical component of the projectile's initial velocity.
Given:
Δy = 2.3 m
v = 0 m/s
a = -9.8 m/s²
Find: v₀
v² = v₀² + 2aΔy
(0 m/s)² = v₀² + 2 (-9.8 m/s²) (2.3 m)
v₀ = 6.71 m/s
Find the horizontal component of the projectile's initial velocity using trigonometry.
tan 40° = 6.71 m/s / v
v = 8.00 m/s
Momentum is conserved:
(0.47 kg) (0 m/s) = (0.050 kg) (8.00 m/s) + (0.47 kg − 0.050 kg) v
v = -0.95 m/s
The cart recoils at 0.95 m/s.