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3 years ago

How are you going to identify a tool that is still functional

1 answer:

7 0

These tools enable the specific execution of a task or a group of tasks allowing the fulfillment of specific objectives within different stages of product development

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The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about

nadya68 [22]

Answer:

a) 4.45 m/s

b) 0.9 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 1}\\\Rightarrow u=4.45\ m/s$

a) The vertical speed when the player leaves the ground is 4.45 m/s

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-4.45}{-9.81}\\\Rightarrow t=0.45\ s$

Time taken to reach the maximum height is 0.45 seconds

$s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1\times 2}{9.81}}\\\Rightarrow t=0.45\ s$

Time taken to reach the ground from the maximum height is 0.45 seconds

b) Time the player stayed in the air is 0.45+0.45 = 0.9 seconds

6 0

3 years ago

What is the mass of a 735-N weight on Earth?

Allisa [31]

W = mg, Assuming g ≈ 9.8 m/s² on the earth surface.

735 N = m* 9.8

735/9.8 = m

75 = m

Mass , m = 75 kg. B.

3 0

3 years ago

I need the answer asap everyone have a good day bye

Slav-nsk [51]

Im pretty sure its A cuz is closer to the earth.

5 0

3 years ago

Which of the following is an advantage of asexual reproduction compared to sexual reproduction?

azamat

Answer:

Asexual reproduction requires less energy and will produce more offspring over time

Explanation:

6 0

3 years ago

Read 2 more answers

Block A weighs 14 lb and block B weighs 5 lb If B is moving downward with a velocity (vB)1 = 3 ft/s at t = 0, determine the velo

kolezko [41]

Velocity, va2 = 10.5 ft/s

<u>Explanation:</u>

From the figure:

Length of the cable = Sa + 2Sb = l

∴ vₐ = -2vb

Applying the principle of Impulse and momentum in x-direction

$mv_x_1 + \int\limits^t_t {F_x} \, dt = mv_x_2$

Limit is t1 to t2

$-(\frac{14}{32.2}) (2) (3) - T = \frac{14}{32.2} v_y_2$ -(1)

Applying the principle of Impulse and momentum in y-direction

$mv_y_1 + \int\limits^t_t {F_y} \, dt = mv_y_2$

Limit is t1 to t2

$(\frac{5}{32.2}) (3) - 2T + 3 = -\frac{5}{32.2} \frac{v_y_2}{2}$ -(2)

Solving equation (1) and (2), we obtain

T = 1.6lb

va2 = 10.5 ft/s

8 0

3 years ago

How are you going to identify a tool that is still functional​

How are you going to identify a tool that is still functional