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Ber [7]
2 years ago
6

On January 2, 2014 the price of a share of stock in Company Inc.

Mathematics
1 answer:
alex41 [277]2 years ago
4 0
13.7 decrease from January 13.696 if not rounding
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The initial value of 100 that doubles over each interval.
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Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m
castortr0y [4]

In order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

<h3>What is the tangential speed of the object?</h3>

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of  the gravitation constant, the tangential speed can be given as,

v=\sqrt{\dfrac{Gm}{r}}

Here, {<em>G</em>} is the gravitation constant, (<em>m</em>) is the mass and (<em>r</em>) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

m_E=6. 0 \times10^{24} kg

The value of gravitational constant is,

G=6. 67\times 10{-11}\rm Nm^2/kg^2

The radius of the earth is,

r_E=6. 0 \times 10^6 \rm m

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

brainly.com/question/4933588

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What is the justification for each step in solving the inequality?
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