You can model the population of a certain city between the years 1965 and 1995 by the radical function P(x) = 75,000 ^3sqrt x-19
40. Using this model, in what year was the population of that city 245,000
A.1973
B.1975
C.1979
D.1970
2 answers:
Answer: B. 1975
Step-by-step explanation:
Given: The model of population of a certain city between the years 1965 and 1995 by the radical function
![P(x)=75000\sqrt[3]{x-1940}](https://tex.z-dn.net/?f=P%28x%29%3D75000%5Csqrt%5B3%5D%7Bx-1940%7D)
To find the x year at which population is 245,000, put this in equation we get
![245000=75000\sqrt[3]{x-1940}\\\\\Rightarrow\frac{245000}{17000}=\sqrt[3]{x-1940}\\\\\Rightarrow3.266=\sqrt[3]{x-1940}\\\\\Rightarrow\ x-1940=(3.266)^3..........\text{[by taking cube on both sides]}\\\\\Rightarrow\ x-1940=34.8587\\\\\Rightarrow\ x=1940+34.8587\\\\\Rightarrow\ x=1974.8587\approx1975](https://tex.z-dn.net/?f=245000%3D75000%5Csqrt%5B3%5D%7Bx-1940%7D%5C%5C%5C%5C%5CRightarrow%5Cfrac%7B245000%7D%7B17000%7D%3D%5Csqrt%5B3%5D%7Bx-1940%7D%5C%5C%5C%5C%5CRightarrow3.266%3D%5Csqrt%5B3%5D%7Bx-1940%7D%5C%5C%5C%5C%5CRightarrow%5C%20x-1940%3D%283.266%29%5E3..........%5Ctext%7B%5Bby%20taking%20cube%20on%20both%20sides%5D%7D%5C%5C%5C%5C%5CRightarrow%5C%20x-1940%3D34.8587%5C%5C%5C%5C%5CRightarrow%5C%20x%3D1940%2B34.8587%5C%5C%5C%5C%5CRightarrow%5C%20x%3D1974.8587%5Capprox1975)
Hence, at year 1975 the population of the city is 245,000.
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
<span> If P(x) = 245000... </span>
<span>245000 = 75000(x - 1940)^(1/3) </span>
<span>x ≈ 1975 </span>
You might be interested in
Answer: 0.92
1-4: stay the same
5-9: round up!
Answer:
4) 26+4/842-/×375-^×
5)/^9+37+×+454+12
Step-by-step explanation:
Answer:
Step-by-step explanation:
If you simplify you get 0 = 19/3, which is false. So there is no solution.
c is the answer of this question because the case given is necessary
Answer: 23.75
Step-by-step explanation:
475*.05=23.75
