C = 3.5t....when t = 15
c = 3.5(15)
c = 52.50 <==
The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is
In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then
Answer:
c
Step-by-step explanation:
Answer:
r=5
Step-by-step explanation:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-3*(4*r-8)-(-36)=0
Step by step solution :
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
4r - 8 = 4 • (r - 2)
Equation at the end of step 2 :
(0 - 12 • (r - 2)) - -36 = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
60 - 12r = -12 • (r - 5)
Equation at the end of step 4 :
-12 • (r - 5) = 0
Step 5 :
Equations which are never true :
5.1 Solve : -12 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : r-5 = 0
Add 5 to both sides of the equation :
r = 5
One solution was found :
r = 5
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