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slamgirl [31]
1 year ago
12

(c) Given that the average speed for the entire journey was 80 km/h, form an equation in x and solve the equation.​

Mathematics
1 answer:
Oduvanchick [21]1 year ago
4 0

Answer:

80x = y

Step-by-step explanation:

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WHAT IS THE SURFACE AREA DUE BY FIVE PM WITH STEPS PLZ I WILL GIVE BRAINLIEST ANSWERS
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Answer:

I have the right answer now!

Step-by-step explanation:

Base: 8×8=64

Triangular base: 16×8= 128÷2= 64

All Triangle base added up:64×4= 256

64+256=320

320!

Hope this helps!

Pls give me brainliest!

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He should have subtracted the discount and added the sales tax
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What reason does Frederick Lugard use to justify British imperialism?
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His opinion was that christianity needed to be spread

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3 years ago
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What is the answer?
mezya [45]

Answer:

18.1 cm

Step-by-step explanation:

AD segment breakup: 11=4+7

Pythagorean Theorem:

7^2+b^2=16^2

49+b^2=256

x^2=207

b=sqrt(207)

b=3sqrt(23)

Pythagorean Theorem:

11^2+3sqrt(23)^2=c^2

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So the length of AC is around 18.1 cm

5 0
3 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
3 years ago
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