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Nataly [62]
2 years ago
9

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

gth is given by
Mathematics
1 answer:
Rama09 [41]2 years ago
5 0

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em>   ==>   d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt

=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt

=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt

=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}

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To find the volume of a rectangular prism, like this one, we take the measure of the Width, Length, and Height and multiply them together. So the answer is: 4*4*8. 4*4=16, and 16*8=128, so the answer is 128 Cubic Feet.
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3 years ago
1. Write a rule that will take the triangle to a congruent triangle. Write your rule as (x,y)
olga nikolaevna [1]

Transforming a shape involves changing the size and/or the location of the shape.

  • The rule that will take the triangle to a congruent triangle is (x,y) \to (x,-y)
  • The rule that will take the triangle to a figure that is similar is (x,y) \to (0.5x,0.5y).
  • The rule that will take the triangle to a figure that is not similar or congruent is (x,y) \to (0.5x,2y).

<h3>Rigid transformation</h3>

When a shape is transformed by a rigid transformation, then the image of the shape will be congruent to the original shape.

An example of a rigid transformation is a reflection over the x-axis; and the rule is:

(x,y) \to (x,-y)

So, a rule that will take the triangle to a congruent triangle is (x,y) \to (x,-y)

<h3>Nonrigid transformation</h3>

When a shape is transformed by a nonrigid transformation, then the image of the shape will not be congruent to the original shape, however the original shape and the transformed shape would be similar

An example of a nonrigid transformation is a dilation by a scale factor od 0.5; and the rule is:

(x,y) \to (0.5x,0.5y)

So, a rule that will take the triangle to a figure that is similar is (x,y) \to (0.5x,0.5y)

However, if the x and y coordinates of the shape are dilated by different scale factors, then the resulting shape would neither be similar nor be congruent to the original shape.

A rule that will take the triangle to a figure that is not similar or congruent is (x,y) \to (0.5x,2y).

Read more about transformation at:

brainly.com/question/4289712

6 0
2 years ago
PLEASE HELP!!! I NEED HELP ASAP
Tju [1.3M]

Answer:

y = 6x

Explanation:

This question is asking you to write a linear equation in slope-intercept form, <u>y = mx + b,</u> where m is the slope and b is the y-intercept.

The y-intercept (where the line crosses the y-axis) is visibly 0. As for the slope, you can take two points, I'll use (0,0) and (0.1,0.6) to calculate it.

Slope = y - y/x- x

Slope = (0.6 - 0)/(0.1 - 0) = 0.6/0.1 = 6

Plug in 0 for b and 6 for m and you have an equation.

y = 6x + 0

y = 6x

4 0
1 year ago
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A bee flies 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for fifteen minutes. Then i
Ksenya-84 [330]

A. The equation to find the distance of the flowerbed from the hive is: \frac{x}{20}+\frac{x}{12}+900= 1200 , where x is the distance.

B.  The flowerbed is 2250 feet far from the hive.

<u><em>Explanation</em></u>

Suppose, the distance of the flowerbed from the hive is x feet.

The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.

As, Time=\frac{Distance}{Speed}

So, the time taken by the bee to reach the flowerbed = \frac{x}{20} seconds and the time taken to fly back to the hive =\frac{x}{12} seconds.

The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.

So, the equation will be.......

\frac{x}{20}+\frac{x}{12}+900= 1200\\ \\ \frac{3x+5x}{60}= 300\\ \\ 8x= 60*300\\ \\ 8x=18000\\ \\ x=\frac{18000}{8}=2250

Thus, the distance of the flowerbed from the hive is 2250 feet.

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If the mean of a positively skewed distribution is 126, which of these values could be the median of the distribution?
guapka [62]

Answer:

122 is the right answer not 130

Step-by-step explanation:

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