Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len gth is given by
1 answer:
The length of a curve <em>C</em> parameterized by a vector function <em>r </em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is
In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then
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Answer:
Step-by-step explanation:
If we graphed y=1, then it would be a horizontal line where a point would be on (0,1).
A horizontal line has no slope, and the y-intercept for y=1 is one.
Step-by-step explanation:
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Answer:
You can start by distributing the 3 to the m+4
(3m + 12)
Now you can add on the -5m and simplify
(3m+12-5m)
-2m+12
sorry but can u post a better picture i cant really help if the picture isn’t good
5/50 = 0.1......x 100 = 10% was rejected