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Serhud [2]
3 years ago
14

Plz help me with my math

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer: The answer is C

Step-by-step explanation:

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Colt1911 [192]

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5 0
2 years ago
I have no idea where to start on either of these problems. Would someone explain the steps to me? My teacher hasn’t gone over th
bazaltina [42]

Answer:

Problem 9:  -1/2

Problem 10:  1/5

Step-by-step explanation:

Problem 10:  Label the given ln e^(1/5) as y = ln e^(1/5).

Write the identity e = e.  Raise the first e to the power y and the second e to the power 1/5 (note that ln e^(1/5) = 1/5).  Thus, we have:

e^y = e^(1/5), so that y = 1/5 (answer).


Problem 9:    Let y = (log to the base 4 of) ∛1 / ∛8, or

                            y = (log to the base 4 of) ∛1 / ∛8, or

                             y = (log to the base 4 of) 1 /2

Write out the obvious:              

                            4                                   =   4

Raise the first 4 to the power y and raise the second 4 to the power (log to the base 4 of) 1 /2.  This results in:

                              4^y    =     1/2.  Solve this for y.  

                                 Note that 4^(1/2) = 2, so that 4^(-1/2) = 1/2

Thus, y = -1/2

                   


3 0
3 years ago
Use the law of cosines to write an expression equivalent to b
andrezito [222]

Given:

A triangle ABC.

The given expression for b is:

b=\sqrt{m+n-pq}

To find:

The expression that is equivalent to b.

Solution:

According to the Law of Cosines,

b^2=a^2+c^2-2ac\cos B

It can be written as:

b=\sqrt{a^2+c^2-2ac\cos B}              ...(i)

We have,

b=\sqrt{m+n-pq}                                ...(ii)

On comparing (i) and (ii), we get

m=a^2

n=c^2

p=2ac

q=\cos B

Therefore, the required values are m=a^2,n=c^2,p=2ac,q=\cos B.

3 0
3 years ago
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