First we want to find the amount that will be worth 20.7 after one year and 23.81 after two years
So I assume that
Y =p (1.15)^x
Where
Y 20.7
P ?
X 1 year
20.7=p (1.15)^1
Solve for p
P=20.7÷1.15
P=18
The answer is
Y=18 (1.15)^x
Answer:
You can wait at the front of the luchline and survey every tenth student.
Step-by-step explanation:
This way it is equal for everyone.
Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper =
sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining = 
= 
Using algebraic formula: 

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
Step-by-step explanation:
sum of the ratio=3+3+4=10
now,
angle I = 3/10×180=54
angle II= 3/10×180=54
angle III=4/10×180=72
that shows th given triangle is isoceles
What is x
First you use distributive property
60x+70=26
Next subtract 70 on both sides which gives you -44
60x=-44
Then you divide 60 into -44 which will give you -1.36__36 is repeathing
so X=-1.36 repeading