Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer:
The last one.
Step-by-step explanation:
The solutions with the horizontal lines are wrong because then h(x) would be -1 and 1 respectively.
The subtlety is in the open or closed dot. x ≥ -1 means that -1 is included, which is drawn as a closed dot. x < -1 means that -1 is excluded, which is drawn as an open dot.
Hence the last graph is the correct one.
Step-by-step explanation:
-7(-3r+2)=3r-6
Distribute the - 7
21r-14=3r-6
Add 14
21r=3r+8
Subtract 3r
18r=8
Divide 18r by 8
2.25 should be the answer to r.
Answer:
70.
Step-by-step explanation:
The answer will be A. Hope it help!
