Answer:
B. the variability around the regression line.
Step-by-step explanation:
The standard errors represents the distance (how sparse) the observed values fall from the regression line.
Standard errors for regression are measures of the spread of variables around the average (regression line)
The standard error is dependent on the standard deviation of the observations and the reliability of the test.
When the test is perfectly reliable, the standard error is zero and when unreliable, it is equal to the standard deviation of the observations.
Answer: $9.00
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First off, I think the equation should have a negative 9 in it originally and then you move it to the other side and it becomes positive.
You'll basically complete the square for two equations at the same time. Set it up like this:
(16x^2 + 96x) + (9y^2 - 18y) = 9
Divide everything by 16 to get the x^2 by itself, then divide everything by 9 to get y^2 by itself. You should end up with this.
(x^2 + 6x) + (y^2 - 2y) = 9/144
then complete the square by taking the second term of each polynomial, dividing by two, and squaring it.
For instance the first one will be 6/2 = 3^2 = 9
The next one will be 2/2 =1^2 = 1
Add these to numbers to the polynomials as well as to the other side of the equation to keep it equal. You should end up with this.
(x^2 + 6x+9) + (y^2 - 2y+1) = (9/144)+9+1
Then find a common denominator on the right side of the equals sign and add them all together to get:
(x^2 + 6x+9) + (y^2 - 2y+1) = 1449/144
Factor out the two polynomials
(x+3)^2 + (y-1)^2 = 1449/144
the center of the circle is (-3,1) according to the factored out polynomials and the radius will be the square root of the number on the right side of the equals sign = sqrt(1449/144) = 3.17
As go up the number sequence it is just the number added to get the new number plus 1. For example, since 2+3=5, 5+3=8+1=9
