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kkurt [141]
3 years ago
15

53 - 9y = 1 -7.2 + 2y = -5

Mathematics
1 answer:
telo118 [61]3 years ago
7 0

Answer:

1.1, -5

Step-by-step explanation:

53 - 9y = 1

from equation i

53-9y = 1

-9y= 1-53 = -52

y = -52/-9= 52/9 = 5⁷/₉

-7.2 + 2y = -5

add 7.2 to both sides

2y= -5+7.2 = 2.2

y= 2.2/2 = 1.1

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A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ
jonny [76]

Let \vec r(t),\vec v(t),\vec a(t) denote the rocket's position, velocity, and acceleration vectors at time t.

We're given its initial position

\vec r(0)=\langle0,0,10\rangle\,\mathrm m

and velocity

\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}

Immediately after launch, the rocket is subject to gravity, so its acceleration is

\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}

where g=9.8\frac{\rm m}{\mathrm s^2}.

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}

\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}

and

\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m

\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m

\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}

b. The rocket stays in the air for as long as it takes until z=0, where z is the z-component of the position vector.

10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}

c. The rocket reaches its maximum height when its vertical velocity (the z-component) is 0, at which point we have

-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)

\implies\boxed{z_{\rm max}=125,010\,\rm m}

7 0
3 years ago
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grandymaker [24]
66 because you divide 100 by 90 that multiply that number by 60
6 0
3 years ago
The question is Chan filled his car with 12.85 gallons of gas the next week he filled his car with 9.08 gallons of gas how much
Shkiper50 [21]

Answer:

3.77

Step-by-step explanation:

Do 13.85-9.08 and

u get 3.77

4 0
3 years ago
A warehouse is 55 yards long, 35 yards wide, and 5 yards high. What is the area of the warehouse floor? If the warehouse is fill
amid [387]

Answer:

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

Step-by-step explanation:

First we have to calculate the area, for this we must multiply the length by the width

a = area

l = long = 55yd

w = width = 35yd

a = l * w

a = 55yd * 35yd

a = 1925yd²

to calculate the volume we have to multiply the area by the height

asks us for the volume for half the height so we have to divide the height by 2

a = area = 1925yd²

h = height = 5yd/2 = 2.5yd

v = volume

v = a * h

v = 1925yd² * 2.5yd

v = 4812.5yd³

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

5 0
3 years ago
A person who weighs 100 pounds on earth weighs 16.6 lb on the moon. What is the independent variable? Explain why
Leviafan [203]
Independent variable (IV): something the scientist can change.

Thus, in this case, the IV can be the weight of the person.
5 0
3 years ago
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