Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


66 because you divide 100 by 90 that multiply that number by 60
Answer:
3.77
Step-by-step explanation:
Do 13.85-9.08 and
u get 3.77
Answer:
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Step-by-step explanation:
First we have to calculate the area, for this we must multiply the length by the width
a = area
l = long = 55yd
w = width = 35yd
a = l * w
a = 55yd * 35yd
a = 1925yd²
to calculate the volume we have to multiply the area by the height
asks us for the volume for half the height so we have to divide the height by 2
a = area = 1925yd²
h = height = 5yd/2 = 2.5yd
v = volume
v = a * h
v = 1925yd² * 2.5yd
v = 4812.5yd³
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Independent variable (IV): something the scientist can change.
Thus, in this case, the IV can be the weight of the person.