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2 years ago

Create a real-life representation of the following multiplication problem. Explain what the result represents in the problem.

1 answer:

7 0

The real-life problem will be:- The total number of chocolates is 24 and there are 3 boxes what will be the number of chocolates filled in each box. The number of chocolates in each box will be 8.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The given expression is:-

$24\times \dfrac{1}{3}$ = 8

The real-life problem will be given the as:-The total number of chocolates is 24 and there are 3 boxes what will be the number of chocolates filled in each box. The number of chocolates in each box will be 8.

Hence the number of chocolates in each box will be 8.

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The demand d for a companys product cost x is predicted by the function d(x) = 500-2x. The price p in dollars that the company c

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Answer:

Step-by-step explanation:

The Break Even point is the point at which the cost=revenue

14,980+20x=30x

14,980=10x

1,498=x

a. 1,498 units must be sold to break even. At $20 per unit, the dollar amount will be $29,960

b. The profit function is P(x)=R(x)-C(x)

So P(x)=30x-(14,980+20x)

If you want to solve for this equation just enter the value of x we found for the break even point to get the answer.

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3 years ago

What is the y-intercept and slope of the equation: y=6x+2

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Answer: y intercept is 2 and slope is 6 or 6/1

Step-by-step explanation:

The number in front of x is always the slope in a y=Mx+b equation and the other number is the y intercept

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3 years ago

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vesna_86 [32]

The answer would be 7x.

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3 years ago

Convert each degrees minutes seconds into decimal degrees 351°41’142”

pav-90 [236]

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3 years ago

For each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts. A large shipmen

Stella [2.4K]

Answer:

(a) The p-value of the test statistic should be 0.33.

(b) No, there is not sufficient evidence to reject the entire shipment.

Step-by-step explanation:

We are given that for each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts.

A quality control manager randomly selects 50 of the parts from the shipment and finds that 6 parts are defective.

Let p = proportion of defective parts among the current shipment.

So, Null Hypothesis, $H_0$ : p $\leq$ 10% {means that the defective parts in the shipment is at most 10%}

Alternate Hypothesis, $H_A$ : p > 10% {means that the defective parts in the shipment is greater 10%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of parts that are defective among the current shipment = $\frac{6}{50}$ = 12%

n = sample of parts from the shipment = 50

So, test statistics = $\frac{0.12-0.10}{\sqrt{\frac{0.12(1-0.12)}{50} } }$

= 0.44

The value of z test statistics is 0.44.

(a) Now, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.44) = 1 - P(Z $\leq$ 0.44)

= 1 - 0.67003 = 0.3299 ≈ 0.33

(b) Since, the P-value of test statistics is more than the level of significance as 0.33 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the defective parts in the shipment is at most 10%.

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3 years ago