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1 year ago

What is the approximate volume of a soda can

Mathematics

1 answer:

Nat2105 [25]1 year ago

7 0

Volume for a cylinder is πr^2h
radius is just the diameter divided by 2, so your radius is 1

πx1^2x5=5π
= about 15.71 inches^3

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39 ft/min= ____ yd/s explain your reasoning

givi [52]

Answer:13 yards

Step-by-step explanation:

There are 3 feet in one yard 39 divided by 3 is 13. So 39 feet is 13 yards

6 0

2 years ago

Read 2 more answers

MATH IS HARD. HELP<br> Change the following into a single fraction: 1− (a+b/a−b)

lianna [129]

Answer:

-2b/(a-b)

Step-by-step explanation:

1− (a+b/a−b)

We need to get a common denominator of a-b

1 = (a-b)/(a-b)

Replace 1 with (a-b)/(a-b)

(a-b)/(a-b) - (a+b)/(a-b)

Put over the common denominator

(a-b) - (a+b)

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(a-b)

Distribute the minus sign.

(a-b) - a-b)

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(a-b)

a-a-b-b

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6 0

2 years ago

An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h

LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

$\frac{11}{1+\sqrt{2} } = a^2$

a² = $\frac{11}{2.42}$

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = $2(1+\sqrt{2} ) X (a)^2 X h$

$V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3$

Therefore, the pool can hold 65.84 ft³ of water

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2 years ago

Find the missing number for 1/3 = 3:

RSB [31]

1/3=3:9
since 1×3=3
3×3=9

7 0

3 years ago

Number 34 please guys!!!!!!

GenaCL600 [577]

The answer is obviously three.

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3 years ago