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Anton [14]
2 years ago
6

Suppose you hold a portfolio of two stocks in the healthcare industry. The future outcomes for these stocks depend mainly on the

next healthcare bill to be passed by Congress. The possible outcomes and returns are: Outcome Probability Return for Stock A Return for Stock B 1=Republican Bill 0.8 12% -5% 2=Democratic Bill 0.2 3% 20% What is the expected return and a standard deviation of a portfolio that has 50% of its value in stock A and 50% in stock B?
Business
1 answer:
irina [24]2 years ago
3 0

The expected return and standard deviation of the portfolio is 5.1% and 3.2%.

<h3>What is the expected return?
</h3>

The expected return of the portfolio is the weighted sum of the return of stock A and stock B.

Return of stock A = (0.8 x 12%) + (0.2 x 3%) = 10.20%

Return of stock B = (0.8 x -5%) + (0.2 x 20%) = 0

Weighed sum = 0.5 x 10.20% = 5.1%

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

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g Credit card applicants have an average credit rating score of 667. Assume the distribution of credit scores is Normal with a s
Marizza181 [45]

Answer:

P(X>700)=P(\frac{X-\mu}{\sigma}>\frac{700-\mu}{\sigma})=P(Z>\frac{700-667}{65})=P(z>0.508)

And we can find this probability using the complement rule and excel or a calculator and we got:

P(z>0.508)=1-P(z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the rating score of a population, and for this case we know the distribution for X is given by:

X \sim N(667,65)  

Where \mu=667 and \sigma=65

We are interested on this probability

P(X>700)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>700)=P(\frac{X-\mu}{\sigma}>\frac{700-\mu}{\sigma})=P(Z>\frac{700-667}{65})=P(z>0.508)

And we can find this probability using the complement rule and excel or a calculator and we got:

P(z>0.508)=1-P(z

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Answer:

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