The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.
Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:
(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)
This is the vector equation; getting the parametric form is just a matter of delineating
<em>x</em>(<em>t</em>) = 1 + <em>t</em>
<em>y</em>(<em>t</em>) = 3<em>t</em>
<em>z</em>(<em>t</em>) = 6 + <em>t</em>
Answer:
2x-3
Step-by-step explanation:
f(x) = 3x-1
g(x) = x+2
Find (f-g)(x), this means we need to subtract g from x.
(3x-1) - (x+2)
Subtract the like terms:
3x -x = 2x
-1 -2 = -3
Combine them to get 2x-3
Answer:
140...........
Step-by-step explanation:
plz make me brainliest
To graph the equation of the line, find the x-intercept and the y-intercept of the function
we have
we know that
The x-intercept is the value of x when the value of y is equal to zero
The y-intercept is the value of y when the value of x is equal to zero
Step 1
<u>Find the x-intercept</u>
For 
the x-intercept is the point 
Step 2
<u>Find the y-intercept</u>
For 
the y-intercept is the point 
Step 3
Graph the points and draw the line
see the attached figure
therefore
the answer in the attached figure
Answer:
1/x and x⁻¹
Step-by-step explanation:
(x⁻³)^⅓
x⁻³*⅓
x⁻¹
1/x
I hope this helps
