Answer:
256/3 = 85 1/3 square inches
Step-by-step explanation:
The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...
A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches
The sum of an infinite series with first term 64 and common ratio 1/4 is ...
S = a1/(1 -r) . . . . . . for first term a1 and common ratio r
= 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches
The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.
<h2>
Answer:</h2><h2>
The 97th term in the series is 409</h2>
Step-by-step explanation:
The given sequence is 25, 29, 33, ....
The sequence represents arithmetic progression
In an AP, the first term is a1 = 25
The difference between two terms, d = 29 - 25 = 4
To find the 97th term,
By formula, 
Substituting the values in the above equation, we get
= 25 + (96 * 4)
= 25 + 384
= 409
The 97 th term in the given sequence is 409.
Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.
n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10 OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK
n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42
So the answer is B
Answer:
The area of a circle can be found using the formula 
Step-by-step explanation:
