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alexira [117]
3 years ago
10

Neveah has created the function f(x) =the quantity of 2x plus 4, divided by 3 to represent the growth of her hair, where x repre

sents the number of months since her last hair cut. Neveah discovers that, using the inverse function to solve for x = 6, she can predict when her hair will have grown 6 inches. Explain to Neveah how to accomplish this, using complete sentences. (10 points)
Mathematics
1 answer:
dangina [55]3 years ago
3 0

Given that:

The function to represent the growth of Neveah hair is

f(x)=\dfrac{2x+4}{3}

where,  x represents the number of months since her last hair cut.

To find:

The inverse of function and time when her hair will have grown 6 inches.

Solution:

We have,

f(x)=\dfrac{2x+4}{3}

Put f(x)=y.

y=\dfrac{2x+4}{3}

Interchange x and y.

x=\dfrac{2y+4}{3}

Isolate y.

3x=2y+4

3x-4=2y

\dfrac{3x-4}{2}=y

Put y=f^{-1}(x).

f^{-1}(x)=\dfrac{3x-4}{2}

So, the required inverse function is f^{-1}(x)=\dfrac{3x-4}{2}. It represents the number of months to grow her hair x inches.

She can predict when her hair will have grown 6 inches by putting x=6 in the inverse function.

Put x=6 in the inverse function.

f^{-1}(6)=\dfrac{3(6)-4}{2}

f^{-1}(6)=\dfrac{18-4}{2}

f^{-1}(6)=\dfrac{14}{2}

f^{-1}(6)=7

Therefore, growth of her hair is 6 inches in 7 months.

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Answer:

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Step-by-step explanation:

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3 years ago
A truffle recipe uses 10 ounces of dark chocolate to make 60 truffles. How many truffles can a baker make with 3 pounds of dark
maxonik [38]

Answer:

240

Step-by-step explanation:

ok, so first you look closely at the problem. convert pounds to ounces, since you dont have enough to do it the other way. so if 1 pound is 16 ounces, 3 pounds is 48. he has 48 ounces. if 10 ounces makes 60, 40 ounces makes 240. now you have 8 left. now im not sure about this part, but if you took the 8 left over, and if 10 ounces makes 60, 8 ounces makes 48 more.

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2 years ago
(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

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Multiply by (-1) on both sides

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Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

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Step-by-step explanation:

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