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Gemiola [76]
2 years ago
13

{(4z-7,z-4,z) |z is any real number} z=-5

Mathematics
1 answer:
weeeeeb [17]2 years ago
4 0

The set when z = -5 is {-27, -9, -5}

<h3>How to determine the set elements?</h3>

The set is given as:

{(4z-7,z-4,z) |z is any real number}

When z=-5, we have:

4z - 7 = 4(-5) - 7 = -27

z - 4 = -5 - 4 = -9

z = -5

So, we have:

{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}

Hence, the set when z = -5 is {-27, -9, -5}

Read more about sets at:

brainly.com/question/8053622

#SPJ1

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Mate, stop repeating questions, wait until your question has been answered.


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180 - 27 = $153 paid.


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200 - 40 = $160 paid.


Therefore Sport City offered the better deal.
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So, $60 x 1.60 =

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Elan Coil [88]

First, let's cancel out the x by multiplying 2x + 18y = -9 by -2.

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Then, we combine the two equations.

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18y - 36y = -18y

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Our new equation is -18y = -9.

Now, divide both sides by -18.

-18y / -18 = y

-9/ -18 = 1/2

y = 1/2

We can plug in a value for y since y = 1/2 now.

Let's use 2x + 18y = -9

Plug in y.

2x + 18(1/2) = -9

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Then, subtract 9 from both sides.

2x = -18

Divide by 2.

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