Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
Answer:
x=65
Step-by-step explanation:
Step 1: Add -3 to both sides.
√x−1+3+−3=11+−3
√x−1=8
Step 2: Solve Square Root.
√x−1=8
x−1=82(Square both sides)
x−1=64
x−1+1=64+1(Add 1 to both sides)
x=65
Check answers. (Plug them in to make sure they work.)
x=65(Works in original equation)
Answer:
y=3/5x
Step-by-step explanation:
Im pretty sure this is the correct answer
M is always positive is not true.
Hope this helps!
