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Brilliant_brown [7]
2 years ago
7

Complete the equation of this circle: (x − [?])²+(y - [ ])²=[ ]

Mathematics
1 answer:
Neko [114]2 years ago
7 0

Answer:

(x-{-2})^2+(y-{4})^2={36}

Equation:

x^2+y^2=r^2

r=radius

Blank following x/y is flipped center(of circle) coordinate for x/y

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13 Answer:
Marizza181 [45]

Step-by-step explanation:

13.

132 miles in 3 h = 132miles/3hours = 132/3 miles/h =

= 44 miles/h

so,

how long for 110 miles ?

speed = distance/time

time = distance/speed = 110 miles / 44 miles/h =

= 110/44 h = 55/22 h =

= 5/2 h = 2.5 h

14.

60% = 60/100 = 6/10 = 3/5

15.

300% = 300/100 = 3

16.

116 2/3% = (348 + 2)/3% = 350/3% = 350/3/100 =

= 350/300 = 1 50/300 = 1 1/6

17.

19% = 19/100

18.

3.8% = 3.8/100 = 38/1000 = 19/500

19.

166 2/3% = (498 + 2)/3% = 500/3% = 500/3/100 =

= 500/300 = 5/3 = 1 2/3

20.

4/5 = 0.8 = 80%

21.

7/4 = 1.75 = 175%

22.

1/3 = 0.3333333... ≈ 33.33%

23.

2 = 200/100 = 200%

24.

0.4 = 40%

25.

0.375 = 37.5/100 = 37.5%

26.

80% of 60 = 60×80/100 = 60×4/5 = 48

27.

24% of 65 = 65×24/100 = 65×6/25 = 13×6/5 =

= 15.6

28.

115% of 138 = 138×115/100 = 138×23/20 =

= 69×23/10 = 158.7

29.

18.3% of 74 = 74×18.3/100 = 74×183/1000 =

= 37×183/500 = 13.542 ≈ 13.54

30.

6.5% of 115 = 115×6.5/100 = 115×65/1000 =

= 23×13/40 = 7.475 ≈ 7.48

31.

0.75% of 93 = 93×0.75/100 = 93×75/10000 =

= 93×3/400 = 0.6975 ≈ 0.70

4 0
2 years ago
Find the dimensions of the square <br> Area=441cm over 2
MA_775_DIABLO [31]

Answer:

each side is 55.125cm

Step-by-step explanation:

you have to divide the area by 2

then do 441/2=220.5

then divide this by 4 because a square has 4 equal sides so 220.5/4=55.125

5 0
3 years ago
If an exam is 75 questions long, a 100% being the highest grade, and 79% and below is failing, how many questions can you miss i
natita [175]
It's a C + 

You did a well! 

Hope this helped!
6 0
4 years ago
Read 2 more answers
Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
The population of current statistics students has ages with mean muμ and standard deviation sigmaσ. samples of statistics studen
Aleonysh [2.5K]

What does the central limit theorem tell us about the distribution of those mean​ ages?

<span>A.    </span>Because n>30, the sampling dist of the mean ages can be approximated by a normal dist with a mean u and a SD o/sqrt 54,

Whenever n<span>>30 the central limit theory applies.</span>

6 0
3 years ago
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