Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer: D (5/2, -17/4)
Step-by-step explanation: Using elimination your goal is to get rid or 1 variable so you can solve for the one that's left. By adding the -2y and 2y you will get 0. You will also add the 3x+x (4x) and -1+11 (10). You have now gotten rid of the y and have 4x=10. By dividing each side by 4 we now know x =2.5. D is the only possible solution with x=2.5 (5/2) but to solve for y you plug 2.5 in to an equation as x so) x-2y=11
2.5-2y=11
-2y=8.5 Answer D (5/2,-17/4) y=-17/4 (4.25)
I am big pp lol xD hxyjdrh
Answer is D. <em><u>288</u></em> . i am glad to help
