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natulia [17]
2 years ago
8

I need answer quickly

Mathematics
2 answers:
Anton [14]2 years ago
4 0

Answer:

√85

Step-by-step explanation:

a² + b² = c²

6² + b² = 11²

36 + b² = 121

b² = 121 - 36

b² = 85

b = √85

g100num [7]2 years ago
3 0

Answer:

Hello! The answer is b = \sqrt{85}.

Step-by-step explanation:

To solve this question, we have to use the Pythagorean theorem. We are given one of the legs and the hypotenuse. (The hypotenuse is opposite the right angle).

a^2 and b^2 represent our legs while c^2 represents the hypotenuse.

We have to substitute our values in for a^2 and c^2:

6^2 + b^2 = 11^2

This leaves us with 36 + b^2 = 121

To get b^2 by itself, we have to subtract 36 from both sides:

36 + b^2 = 121

-36             -36


This leaves us with b^2 = 85

To get just b, we have to take the square root:

√b^2 = √85

This leaves us with b = \sqrt{85}.

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These angels are equal. What are they called?
Yanka [14]
Acute angles because they are less then 90 degrees which is a right angle.

7 0
4 years ago
Pleaseee someone help me :( Ive been stuck on this for an hour
Whitepunk [10]

Answer:

The number of times organism B's population is larger than organism A's population after 8 days is 32 times

Step-by-step explanation:

The population of organism A doubles every day, geometrically as follows

a, a·r, a·r²

Where;

r = 2

The population after 5 days, is therefore;

Pₐ₅ = = 32·a

The virus cuts the population in half for three days as follows;

The first of ta·2⁵ he three days = 32/2 = 16·a

The second of the three days = 16/2 = 8·a

After the third day, Pₐ = 8/2 = 8·a

The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;

P₈ =  a·2⁸ = 256·a

Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times

Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.

Hope this helps you out! :)

Also, it's OK! This was actually pretty hard to figure out!

6 0
4 years ago
How can I solve this question???
eduard

Answer:

144°

Step-by-step explanation:

step 1

Find the measure of the central angle of the regular pentagon

Divide 360 degrees by 5 (the number of sides)

360\°/5=72\°

Let

c----> the center of the pentagon

we know that

m∠ECA=72°

m∠ACB=72°

therefore

m∠ECB=m∠ECA+m∠ACB

substitute the values

m∠ECB=72°+72°=144°

The measure of angle ECB is equal to the degrees that the pentagon rotate

5 0
3 years ago
Help me plzzzzzzzzzzzzzzzzzz.
blagie [28]

Answer:

D : 10ab√2a+20a√2a

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do you do this and what are the answers
scoray [572]
I can answer 1 to 4...
The area of a circle can be found by \pi r^{2}. Reminder: \pi = 3.14 (usually used when finding out the area of a circle)

1. 4^{2} = 16
\pi *16 or 3.14 * 16 = 50.24
50.24/4=12.56

2. 6^{2} = 36
\pi *36 or 3.14 * 36 = 113.04
113.04/10=11.304

(Not really sure if this is correct) 3. 2^{2}=4
\pi *4 or 3.14 * 4
12.56/2.66666667=11.70999999

4. 6^{2}=36
\pi *36= 113.04
113.04/6=18.84
5 0
3 years ago
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