Answer:
![\frac{1625z^{10}}{x^{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B1625z%5E%7B10%7D%7D%7Bx%5E%7B5%7D%7D)
Step-by-step explanation:
We want to simplify:
![\frac{13x^{-5}y^0}{5^{-3}z^{-10}}](https://tex.z-dn.net/?f=%5Cfrac%7B13x%5E%7B-5%7Dy%5E0%7D%7B5%5E%7B-3%7Dz%5E%7B-10%7D%7D)
We rewrite as positive index to get:
![\frac{13y^05^{3}z^{10}}{x^{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B13y%5E05%5E%7B3%7Dz%5E%7B10%7D%7D%7Bx%5E%7B5%7D%7D)
This simplifies to
![\frac{13*1*125z^{10}}{x^{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B13%2A1%2A125z%5E%7B10%7D%7D%7Bx%5E%7B5%7D%7D)
This will finally give us:
![\frac{1625z^{10}}{x^{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B1625z%5E%7B10%7D%7D%7Bx%5E%7B5%7D%7D)
We cannot simplify further.
Hence the simplest form is ![\frac{1625z^{10}}{x^{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B1625z%5E%7B10%7D%7D%7Bx%5E%7B5%7D%7D)
Answer: closed circle pointing to the right.
Step-by-step explanation:
Given that the inequality equation is
6 ( 2 - 3y ) < = 36
Open the bracket
12 - 18y < = 36
Collect the like terms
- 18y < = 36 - 12
Make y the subject of formula
The inequality sign will change the moment you multiply or divide both sides by negative numbers
Y > = - 24/18
Y > = - 4/3
That is y is greater than or equal to negative 4/3
Graphing the above inequality,
The point will be between -2 and -1. And it will be closer to -1.
The arrow will point to the right and it will be a closed circle since it is greater than or equal to.
The correct unit for this triangle would be cm. Hope this helps!
You can multiply the fraction by any number you want so the new fraction gonna be equivalent to your fraction like : (4 × 2)/(5 × 2) = 8/10 or (4 × 3) / ( 5×3) = 12/15 so 4/5 = 8/10 = 12/15 :))
i hope this be helpful
have a nice day
"45 years or over" includes all of the age groups "45-64", "65-74", and "75 or over". These age groups are disjoint (no individual can belong to more than one group), so the probability of picking someone that's at least of 45 years of age is the sum of the probabilities that a person belongs to any one of these groups. That would be