All categories

3 years ago

Help plz:)))I’ll mark u Brainliest

Mathematics

1 answer:

11111nata11111 [884]3 years ago

5 0

<h3>Answer: 66.48</h3>

=============================================================

Explanation:

The formula we'll use to find the surface area is:

SA = 4*pi*r^2

In this case, the radius is r = 2.3 meters

SA = 4*pi*r^2

SA = 4*pi*(2.3)^2

SA = 66.47610054996

SA = 66.48 square m

You'll type the expression you see for step 2 into your calculator to get the result of step 3. The result is approximate. Let your calculator handle the decimal digits of pi as your teacher instructs. The last step is us rounding to two decimal places. The units for the surface area are in square meters, because we can effectively unwrap the outer surface (think of it like unwrapping a present) to lay it out flat.

You might be interested in

At 12 noon, leslie recorded the temperature as 56 degrees f. The temperature had increased by 8 degrees f from 10am. The tempera

Marat540 [252]

Let the temperature at 10am be x, then
x + 8 = 56
x = 56 - 8 = 48 degrees F

Let y be the temperature at 8am, then
y - 2 = 48
y = 48 + 2 = 50 degrees.

4 0

3 years ago

Read 2 more answers

$7230 for 3.25% in 12 years

IceJOKER [234]

$2,819.70 is the answer

You multiply .0325×12×72.30

6 0

3 years ago

At a family reunion, a family friend bring 20 lb of ice and 30 cup. Which expression show the greatest common factor , using dis

Zepler [3.9K]

Answer:

10(2+3)

Step-by-step explanation:

We are given that

Ice=20 lb

Cup=30

We have to find the expression which shows the greatest common factor using distributive property of 20 and 30.

We know that distributive property of integers a,b and c

$a\cdot(b+c)=a\cdot b+a\cdot c$

$20=2\times 10$

$30=3\times 10$

$10(2+3)=10\times 2+10\times 3$

Hence, the highest common factor of 20 and 30=10

Expression:10(2+3)

3 0

3 years ago

Find the general solution of the given differential equations. Give the largest interval I over which the general solution is de

e-lub [12.9K]

The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)

The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
</span>
The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>

4 0

3 years ago

Someone please help ASAP will give brainliest

sesenic [268]

Answer:

the answer is 2

Step-by-step explanation:

6 0

3 years ago