12. Create a two-way relative frequency table (in decimals) for the data in Exercise 9. Communication Gender Male Femal e Total
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Let the length be 
in this equation.
We know that the perimeter of a rectangle is
Width is defined in terms of length, so we know
We can substitute this value of w into the formula for perimeter to find the length.
So the length is 37. Now that we've found the length, we can go back to the Perimeter formula again and find width.
Width is 54. Now with both of these values found, we can calculate area with the formula
So the area of the rectangle is 1998 yards^2.
We know that the perimeter of a rectangle is
Width is defined in terms of length, so we know
We can substitute this value of w into the formula for perimeter to find the length.
So the length is 37. Now that we've found the length, we can go back to the Perimeter formula again and find width.
Width is 54. Now with both of these values found, we can calculate area with the formula
So the area of the rectangle is 1998 yards^2.
Given:
Distance between two buildings = feet apart.
Distance between highway and one building = feet.
Distance between highway and second building = feet.
To find:
The standard form of the polynomial representing the width of the highway between the two building.
Solution:
We know that,
Width of the highway = Distance between two buildings - Distance of both buildings from highway.
Using the above formula, we get the polynomial for width (W) of the highway.
Combining like terms, we get
Therefore, the width point highway is .