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3 years ago

Describe each polynomial expression by type and components based on the example shown. 3x^2 + 2x 2x^2 − 5x + 3 6x

Mathematics

2 answers:

miss Akunina [59]3 years ago

6 0

Answer:

Its Easy 63137x7821/767382(87438>989)8788123.

Step-by-step explanation:

Tanzania [10]3 years ago

5 0

Answer:

gy gyū,hn

Step-by-step explanation:

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PLZZZ HELP FOR BRAINLIST

lina2011 [118]

Answer:

I D K GUESS ITS 1 2 4 I GUESS THINKING

Step-by-step explanation:

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2 years ago

Which three points in the figure are collinear?

adelina 88 [10]

I’m sorry I’m stuck

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2 years ago

Read 2 more answers

how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

2 years ago

Find the qoutient 1 1/6 / 1/12

anygoal [31]

Answer:

Step-by-step explanation:

$1\frac{1}{6}\div\frac{1}{12}\\ \\ \frac{7}{6}\div\frac{1}{12}\\ \\\frac{7}{6}*\frac{12}{1}\\ \\\frac{84}{6}\\ \\14$

8 0

1 year ago

so I think I got nine correct but 10-11 are part of the same problem and I'm not sure to go from here

NemiM [27]

$\begin{gathered} 10.\text{ }(\angle1+\angle3)+90^{\circ}+17^{\circ}=180^{\circ} \\ \Rightarrow(61^{\circ}+\angle3)=180^{\circ}-90^{\circ}-17^{\circ} \\ \Rightarrow\angle3=73^{\circ}-61^{\circ} \\ \Rightarrow\angle3=12^{\circ} \end{gathered}$ $\begin{gathered} 11. \\ \Rightarrow\angle2+\angle3+17^{\circ}=180^{\circ} \\ \Rightarrow\angle2+12^{\circ}+17^{\circ}=180^{\circ} \\ \Rightarrow\angle2=180^{\circ}-29^{\circ} \\ \Rightarrow\angle2=151^{\circ} \end{gathered}$

7 0

9 months ago