Question

Write the equation of the line that passes through the points (8,-1) and (2,-5) in standard form, given that the point-slope form is y+1=3/3(x-8)

Answer 1

The equation of the line that passes through the points (8,-1) and (2,-5) is 2x - 3y = 19.

The given coordinate are (8, -1) and (2, -5).

What is the slope of an equation?

In mathematics, the slope or gradient of a line is a number that describes both the direction and the steepness of the line.

The slope of the equation is $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$.

The standard form of an equation is Ax + By = C.

The given the point-slope form is $y+1=\frac{2}{3} (x-8)$.

Multiply each term by 3 of the equation.

$(y+1) \times3=\frac{2}{3} (x-8) \times3$

⇒3y + 3 = 2x - 16

Subtract 2x from both sides of a equation.

That is, -2x + 3y + 3 = - 16

Subtract 3 from both sides of a equation.

That is, -2x + 3y = - 19

Multiply each term by - 1 from both sides of an equation.

That is, 2x - 3y = 19

Therefore, the equation of the line that passes through the points (8,-1) and (2,-5) is 2x - 3y = 19.

To learn more about the slope visit:

brainly.com/question/3605446.

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