Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
i cant see it
Step-by-step explanation:
Represent the total number of boxes that both jean and clint stack in h hours,
total number of boxes=(50xh)+(60xh)
you want the total number of boxes for both of them together. so the amount they can stack times h or the hours. so if h=5 you would do 50x5 plus+ 60x5 which would give you 250 and 300. add the two you get 550 boxes for 5 hours total.
360 blinks / 30 minutes = 12 blinks per minute
12 blinks per minute x 9 minutes = 108 blinks
Answer: 108
