<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1
Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
Answer:
First of all the rate of change is -2, so the answer would be y = x - 2
Answer:
y=1/3x-3
Step-by-step explanation:
use the eqation y-y1 = m(x-x1)
plug in slop as m and points as x and y
so now you have --> y-(-4)=1/3(x-(-3))
two negatives = a positive --> y+4=1/3(x+3)
distribute the 1/3 --> y+4= 1/3x + 1
subtract 4 from both sides --> y= 1/3x - 3
Answer:
Step-by-step explanation:
The correct answer is y=2/3x
To find the slope you use rise over run so you take one dot (2,-5) and go up 2 units so that it would get one the same line as the other dot (5,-3) and then go to the right 3 units to get you to the exact spot that the dot is
