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poizon [28]
2 years ago
12

Which of the following is equal to m

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

Answer: tan^-1 (c/a)

Step-by-step explanation: An angle C ∈ ℝ such that angle C > 0 can be defined by the trigonometric ratio Arctangent (or rather tan^-1) where side "c" divided by side "a" ≠ 0.

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1. A tortoise is running on a long, moving sidewalk. Her pedometer doesn't report her speed, but she knows that—since she got on
Burka [1]

Answer:

the sidewalk speed q = 3km/hr

the tortoise speed p is 1.5 km/hr

Step-by-step explanation:

From the given information:

let the speed of the tortoise be p  & the speed of the sidewalk be q

she's been running for 40 minutes (40/60 = 2/3) and that she's travelled 3 kilometres

Thus,

p + q = \dfrac{3}{\dfrac{2}{3}}

p + q = 9/2

p + q = 4.5 ----- (1)

when returning, she travelled 3km in 2 hours

i.e. -p + q = 3/2

-p + q = 1.5   ----- (2)

Thus, by using the elimination method for equation (1) and (2)

  p + q = 4.5  ----- (1)

<u>-p + q   = 1.5 ----- (2)  </u>

<u>       2q =  6               </u>

q = 6/2

q = 3 km/hr

From equation (1)

p + q = 4.5

p + 3 = 4.5

p = 4.5 - 3

p = 1.5 km/hr

Therefore, the sidewalk speed q = 3km/hr and the tortoise speed p is 1.5 km/hr

8 0
3 years ago
Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3
Serhud [2]

Answer:

e^{3t}(2t+5t^{2})

Step-by-step explanation:

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem:L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]

Separate the fraction in a sum:

e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])

The formula for this is:

L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}

Modify the expression to match the formula.

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])

Solve

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )

6 0
3 years ago
Nathan needs to graph the ordered pair (-3, -8). In which quadrant will he graph the ordered pair&gt;
Nadusha1986 [10]
The answer is Quadrant 3
8 0
3 years ago
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Which statement is true?
blagie [28]
A is the correct answer
4 0
3 years ago
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Common ration of 54 and 72
Zepler [3.9K]

Answer:try 75% if that does not work try 128 , 96 , 72 , 54. 128 128 , 96 96 , 72 72 , 54 54

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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