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2 years ago

Hugo is the chef of a school cafeteria.

Mathematics

2 answers:

bonufazy [111]2 years ago

8 0

Answer:

Step-by-step explanation:

Because 15 is with a different number other then 180, then it isn't linear, or graphable. It won't be a function if you have the same number with different numbers. The input and output won't make sense.

Licemer1 [7]2 years ago

7 0

Answer: No

Step-by-step explanation:

I guessed..but it was right

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The upper quartile for the data set given below is. 14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29

LekaFEV [45]

Ok, first we need to organize.
14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29
3, 8, 9, 11, 12, 14, 17, 22, 23, 27, 29.

First, we need to find the median, the or the middle, which is 14.
Now that we know the median is fourteen, we take away all numbers to the left of 14, including 14: 17, 22, 23, 27, 29. Now just find the median in this new set of numbers. This will give us our upper quartile, which is 23. Hope this helped, and don't forget to drop a like.

5 0

3 years ago

Rewrite in Polar Form.... x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago

In Triangle JKL the measure of angle J = 40 and the measure of angle L is 3 times the measure of angle K. Find the measure of an

damaskus [11]

Answer:

Step-by-step explanation:Im sorry I can't answer this because you didn't give me the finished number

7 0

3 years ago

Point B is the midpoint of AC, and point C is the midpoint of AD. If CD=12, what is AB?

Sliva [168]

Answer: AB = 6

Step-by-step explanation:

If CD = 12 , AC also = 12

B is the midpoint of AC so one side = 6

AB is one side of AC , so AB = 6

I am not a professional, I am simply using prior knowledge!

Note- It would mean the world to me if you would mark me brainliest!

4 0

2 years ago

In the triangle below, the value of a is 12.6. True False

aev [14]

Answer:

True

Step-by-step explanation:

Formula

Tan(x) = opposite / adjacent

Givens

x = 42

adjacent = 14

opposite = ?

Solution

Tan(42) = opp/14 Find tan(42)

Tan(42) = 0.900404

0.900404 = opp/ 14 Multiply both sides by 14

14 * 0.900404 = opp/14 * 14 Simplify the left

12.6 rounded = opp

a = 12.6

7 0

3 years ago