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3 years ago

What percent is equivalent to 9/4 ? A) .225% B) 22.2% C) 44.4% D) 225%

Mathematics

1 answer:

ki77a [65]3 years ago

8 0

Your answer would be D. 225%. 9/4 equals to 2.25 which multiplied but a 100 to make the percentage equals 225%.

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what is the result of dividing 48a^3 + 32a^2 + 16a by 4a? A. 12a^2 + 8a + 4 B. 12a^2 + 4a + 8 C. 12a + 8 D. 12a^2 + 4a + 4 Simpl

lora16 [44]

Answer:

1. A. 12a^2 + 8a + 4

2. C. 4xy+16x-4y^2-16y

3. C. 64q^6r^8s^4

4. A. -4x^4y^6

Step-by-step explanation:

48a^3 + 32a^2 + 16a / 4a = (48a^3) / 4a + (32a^2) / 4a + (16a) / 4a = 12a^2 + 8a + 4.

So, the answer is A. 12a^2 + 8a + 4.

(2x-2y)(2y+8) = 4xy - 4y^2 + 16x - 16y.

So, the answer is C. 4xy+16x-4y^2-16y.

(-8q^3 * r^4 * s^2)^2 = (-8)^2 * q^6 * r^8 * s^4 = 64q^6r^8s^4.

So, the answer is C. 64q^6r^8s^4.

-12x^8y^8 / 3x^4y^2 = (-12 / 3) * (x^(8 - 4)) * (y^(8 - 2)) = -4x^4y^6.

So, the answer is A. -4x^4y^6.

Hope this helps!

6 0

4 years ago

Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal

a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

$\dfrac{1}{x}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{y + 49 + y}{y^{2} + 49 y }$ = $\dfrac{1}{49}$

Or, 2 y + 49 = $\dfrac{y^{2}+49y }{19}$

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = $\frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, y = $\frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}$

Or, y = $\frac{- 1 \pm \sqrt{121+3724}}{2}$

or, y = $\frac{- 1 \pm \sqrt{3845}}{2}$

or, y = $\frac{- 1 \pm 62.008}{2}$

∴ y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0

3 years ago

Find the missing side of the triangle. leave your answer in simplest radical form

KIM [24]

missing side is $x} = 10.15$ mi .

<u>Step-by-step explanation:</u>

Here we have the following info from the figure: A right angled triangle with following dimensions

$Perpendicular = x$

$base = \sqrt{122}$

$Hypotenuse = 15$

By Pythagoras Theorem :

$Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $15^2 = x^2 + (\sqrt{122})^2$

⇒ $225 = x^2 + 122$

⇒ $x^2 = 225-122$

⇒ $x^2 = 103$

⇒ $(x^2)^\frac{1}{2} = (103)^\frac{1}{2}$

⇒ $x} = (103)^\frac{1}{2}$

⇒ $x} = 10.15$

Therefore, missing side is $x} = 10.15$ mi .

8 0

3 years ago

A toy car can go 3 mph. How long would it take to go 10 miles?

dedylja [7]

Answer:

2 2/3 hours

Step-by-step explanation:

if the car can go 3 miles per hour that means it can go 10 miles in 2 2/3

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3 years ago

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34kurt

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6 0

3 years ago