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hram777 [196]
3 years ago
13

Chevy has some yarn that he wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each sc

arf uses 0.10.10, point, 1 kilograms of yarn. Chevy wants to use 222 kilograms of yarn to make a total of 151515 items. Let hhh be the number of hats Chevy makes and sss be the number of scarves he makes. Which system of equations represents this situation? Choose 1 answer:
Mathematics
1 answer:
Rashid [163]3 years ago
5 0

Answer:

The system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.

Step-by-step explanation:

Let number of hat Chevy makes be h.

Also Let number of scarves Chevy makes be s.

Given:

Total Amount of yarns = 2 kg

Total number of items = 15

Since Items need to make are hat and scarves.

Hence the equation can be represented as;

h+s=15 \ \ \ \ equation \ 1

Again Given:

Each hat uses 0.2 kilograms of yarn.

each scarf uses 0.1 kilograms of yarn.

Hence the equation can be represented as;

0.2h+0.1s=2 \ \ \ \ \ equation \ 2

Hence the system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Now Solving these to find number of hats and number of scarves.

Multiplying equation 2 with 10 we get;

10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3

Now Subtracting equation 1 from equation 3 we get;

(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5

Now Substituting the value of h in equation 1 we get;

h+s= 15\\5+s =15\\s=15-5\\s=10

Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.

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Probability is the department of mathematics regarding numerical descriptions of ways likely an occasion is to occur, or how possibly it's far that a proposition is genuine. The possibility of an occasion varies between zero and 1, wherein, roughly speaking, 0 suggests the impossibility of the occasion and 1 shows certainty. The better the possibility of an event, the more likely it is that the event will arise.  

A simple instance is the tossing of an honest (unbiased) coin. since the coin is truthful, the 2 results ("heads" and "tails") are both equally likely; the possibility of "heads" equals the chance of "tails"; and considering the fact that no different results are feasible, the possibility of both "heads" or "tails" is 1/2 (that could additionally be written as 0.5 or 50%).

To learn more about Probability visit here:

brainly.com/question/11234923

#SPJ4

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