Find the equation for the line passing through the point (−3,−3) and perpendicular to the line whose equation is −1x+2y+2=0.

1 answer:

6 0

First we have to figure out the slop of the given equation:
-1x+2y+2=0
y=1/2x - 1

So the slope is 1/2. A line perpendicular to this line has a slope of the negative reciprocal of this slope. So the slope of the line you want to find is -2.

So: y +3 = -2(x+3).

And you can expand into the form that you want (or just keep it this way). :)

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50 POINTS! PLZ HELP NO ONE HELPED ME LAST TIME BUT I HOPE SOMEONE WILL THIS TIME! ALSO DON'T KNOW WHY I'M WRITING IN ALL CAPS

dalvyx [7]

Answer:

$\frac{90}{3.5}$

Step-by-step explanation:

Let x be the number of helium balloons they can buy

Write it out: 35 + 3.50x = 125
Subtract 35 from each side, so it now looks like this: 3.50x = 90
Divide each side by 3.50 to cancel out the 3.50 next to x. It should now look like this: x = $\frac{90}{3.5}$

I hope this helps!

5 0

2 years ago

Read 2 more answers

Which of the following graphs is a polynomial function with x-intercepts of (-3,0)(-1,0), and (2,0)?

Helen [10]

The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.