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Serjik [45]
1 year ago
6

Please help me solve this LCM​

Mathematics
1 answer:
hodyreva [135]1 year ago
7 0

Note that

x^2 - y^2 = (x - y) (x + y)

and

x^2 + 2xy + y^2 = (x + y)^2

Then their LCM is \boxed{x + y}.

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Two similar triangles are shown below: Which two sets of angles are corresponding angles? ∠w and ∠v; ∠x and ∠y ∠w and ∠y; ∠x and
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I think the 2nd one I'm not really sure
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3 years ago
Steffie makes a scale drawing for a crate with the demensions 15 inches long by 12 inches wide. Her scale factor is 1:3. Brian m
rodikova [14]

Answer:

Dimensions → (5 inches × 4 inches)

Step-by-step explanation:

Scale factor used for the drawing by Steffie = \frac{1}{3}

Since, scale factor = \frac{\text{Dimension of the drawing}}{\text{Actual dimension}}

For Steffie,

Actual length of the crate = \frac{\text{Dimension of the drawing}}{\text{Scale factor}}

                                           = \frac{15}{\frac{1}{3}}

                                           = 45 inches

Actual width of the crate = \frac{12}{\frac{1}{3} }

                                         = 36 inches

Since Brian used the scale factor = \frac{1}{9}

Length of the drawing = Actual length × Scale factor

                                     = 45 × \frac{1}{9}

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Width of the drawing = Actual width × Scale factor

                                   = 36 × \frac{1}{9}

                                   = 4 inches

Therefore, dimensions of the drawing made by Brian are (5 inches × 4 inches)

6 0
3 years ago
Write x^2 − 8x + 13 = 0 in the form (x −
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If you would like to write the equation in the above form, you can calculate this using the following steps:

x^2 - 8x + 13 = 0
(x - 4)^2 = x^2 - 8x + 16
(x - 4)^2 - 3 = 0
(x - 4<span>)^2 = 3
</span>
The correct result would be (x - 4<span>)^2 = 3.</span>
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(32°) = 1700 feet / x => x = 1700 feet / tan(32°) = 1700 feet / 0.625 = 2720 feet. 
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2 years ago
A man runs the London marathon at an average speed of 8mph the route is 26 miles what was his time in hours and minutes
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Answer:

the only thing you need to do is to divide the speed with the distance

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