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rusak2 [61]
3 years ago
13

Which of the following is the solution to Ix-12|​

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

eerwrrwrerwrwrw

Step-by-step explanation:

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Factor completely:<br><br> <img src="https://tex.z-dn.net/?f=3x%5E3%2B21x%5E2%2B36x" id="TexFormula1" title="3x^3+21x^2+36x" alt
guajiro [1.7K]
To factor, you can first treat it like a single bracket and find the common factor. In this case, the common factor is 3x, so you get
3x(x² + 7x + 12)
Now you can factor the bracket normally, by finding factors of 12 that add up to make 7. The factors would be 3 and 4, so the bracket becomes (x + 3)(x + 4).
This leaves your final answer as
3x(x + 3)(x + 4)

I hope this helps!
5 0
3 years ago
Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!
Trava [24]
\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.
--------------------
5y = 12
\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

Let's replace the value found in the first equation:
4x-3y=16\:(I)
4x-3*( \frac{12}{5}) =16
4x -  \frac{36}{5} = 16
least common multiple (5)
\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}
20x - 36 = 80
20x = 80 + 36
20x = 116
x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark



4 0
3 years ago
In a triangle, the midsegment is ___________ to and ____________ of the non-intersecting side.
erastova [34]
In a triangle, the midsegment is parallel to and half of non-intersecting side.
7 0
3 years ago
Read 2 more answers
HELP ! With a deck of playing cards,make up a question with given probability 1. 13/52 • 13/51 • 4/50 • 4/492. 13/52 • 12/51 • 4
kolezko [41]

13/52 : probability of all spades

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