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Gemiola [76]
3 years ago
13

Solve for 2 unknowns : 2a+b=5 ; 3a+2b=9

Mathematics
2 answers:
Vadim26 [7]3 years ago
7 0
Let us take the first equation first
2a + b = 5
Then
b = 5 - 2a
Now we have to put the value of b from the first equation in the second equation. Let us take the second equation now.
3a + 2b = 9
3a + 2(5 - 2a) = 9
3a + 10 - 4a = 9
- a = 9 - 10
- a = - 1
a = 1
Now let us put the value of a in the first equation.
2a + b = 5
2(1) + b = 5
2 + b = 5
b = 5 - 2
   = 3
So the value of the unknown variable a is 1 and the value of the unknown variable b is 3.
MArishka [77]3 years ago
7 0
Have a nice days.........

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Answer:

She would owe $3,700 at the end of 12 month.

Step-by-step explanation:

Simple interest formula:

I=Prt

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Given that, she could borrow $2,500. So P=$2,500.

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The interest I = $(2,500×0.04×12)

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5 0
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Need help with this problem:
Nitella [24]

Answer:

<em>Henson: 3x + y = 163</em>

<em>Garcia: 2x + 3y = 174</em>

<em>adult ticket price: $45</em>

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Step-by-step explanation:

Henson Family:

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Garcia Family:

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Now we solve the system of equations.

Solve the first equation (Henson Family) for y.

y = 163 - 3x

Substitute 163 - 3x for y in the second equation (Garcia Family).

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adult ticket price: $45

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8 0
3 years ago
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