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algol13
2 years ago
15

The rules for a race require that all runners start at $A$, touch any part of the 1200-meter wall, and stop at $B$. What is the

number of meters in the minimum distance a participant must run
Mathematics
1 answer:
mixer [17]2 years ago
5 0

Let the place that they touch be x meters from the 300 m wall

Then the distance from the 500 m wall will be 1200 - x

Then....the total distance, D, can be expressed asD = sqrt [ x^2 + 300^2 ] + sqrt [ (1200 - x)^2 + 500^2 ]

This can be solved with Calculus, but it's a little messy

The graph shows that the minimum distance is achieved when x = 450m

And the minimum distance  ≈  1442 m

By the way......we can show that this is true if

arctan [ 300 / 450]   =  arctan [ 500 / 750 ]  ......and this is true  !!!!

Learn more about Distance:

brainly.com/question/12356025

#SPJ4

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Answer:

7

Step-by-step explanation:

We need to translate all these statements to equations.

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The first statement "3 pistachio and 1 walnut weigh the same as 10 peanuts" can be represented as:

3 P + 1 W = 10 N

The second statement "1 pistachio and 6 peanuts weigh the same as 1 walnut" can be represented as:

1 P + 6 N = 1 W

If we notice, both equations have a similar term: 1 W. The second gives us the equivalence to the weight of 1 walnut, whereas in the first we have the weight of 1 walnut as an unknown variable. Lets replace it!

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4 P + 6 N = 10 P

We now need to sum (-4P) in both sides to eliminate the 4 P on the left:

4 P + 6 N - 4P = 10 P - 4 P

6 N = 6 P

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3 N + 1 W = 10 N

Summing  (-3 N) in both sides:

3 N + 1 W - 3N = 10 N - 3N

1 W = 7 N

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Step-by-step explanation:

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